-16x^2-6x+190=0

Solution for -16x^2-6x+190=0 equation:

-16x^2-6x+190=0

a = -16; b = -6; c = +190;
Δ = b2-4ac
Δ = -62-4·(-16)·190
Δ = 12196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12196}=\sqrt{4*3049}=\sqrt{4}*\sqrt{3049}=2\sqrt{3049}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{3049}}{2*-16}=\frac{6-2\sqrt{3049}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{3049}}{2*-16}=\frac{6+2\sqrt{3049}}{-32}
$